2x^2-4x+2x+3.5=3

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Solution for 2x^2-4x+2x+3.5=3 equation: 



2x^2-4x+2x+3.5=3

We move all terms to the left:

2x^2-4x+2x+3.5-(3)=0

We add all the numbers together, and all the variables

2x^2-2x+0.5=0

a = 2; b = -2; c = +0.5;
Δ = b2-4ac
Δ = -22-4·2·0.5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{2}{4}=1/2$

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